SQUALL to SPARQL Translator

Your SQUALL sentence:

Does 'Tesla' have award 'Nobel Prize Physics'?

The SPARQL translation:

ASK {

?x1 :award ?x2 .
FILTER (REGEX(str(?x2),'Nobel','i') && REGEX(str(?x2),'Prize','i') && REGEX(str(?x2),'Physics','i')) .
FILTER (REGEX(str(?x1),'Tesla','i')) .

}

Run at DBpedia SPARQL endpoint (assuming prefixes res: for resources, : and dbo: for ontology, and dbp: for properties in addition to DBpedia namespace definitions).

Load in DBpedia SPARQL Explorer (assuming the same prefixes as above).