SQUALL to SPARQL Translator

Your SQUALL sentence:

For every person X, for S = concat(every firstname, " ", every lastname) of X, return that X has fullname S.

The SPARQL translation:

CONSTRUCT {
?x1 :fullname ?x4 .
} WHERE { ?x1 a :person .
?x1 :firstname ?x2 .
?x1 :lastname ?x3 .
BIND (concat(?x2," ",?x3) AS ?x4) .
}

Run at DBpedia SPARQL endpoint (assuming prefixes res: for resources, : and dbo: for ontology, and dbp: for properties in addition to DBpedia namespace definitions).

Load in DBpedia SPARQL Explorer (assuming the same prefixes as above).


Enter a SQUALL sentence: