SQUALL to SPARQL Translator

Your SQUALL sentence:

Give me all Film-s whose producer is res:Hal_Roach.

The SPARQL translation:

SELECT DISTINCT ?x1 WHERE {
?x1 a :Film .
?x1 :producer res:Hal_Roach .
}

Run at DBpedia SPARQL endpoint (assuming prefixes res: for resources, : and dbo: for ontology, and dbp: for properties in addition to DBpedia namespace definitions).

Load in DBpedia SPARQL Explorer (assuming the same prefixes as above).


Enter a SQUALL sentence: