SQUALL to SPARQL Translator

Your SQUALL sentence:

Give me all SoccerClub whose dbp:ground is 'Spain'.

SELECT DISTINCT ?x1 WHERE {

?x1 a :SoccerClub .
?x1 dbp:ground ?x2 .
FILTER (REGEX(str(?x2),'Spain','i')) .

}

Run at DBpedia SPARQL endpoint (assuming prefixes res: for resources, : and dbo: for ontology, and dbp: for properties in addition to DBpedia namespace definitions).

Load in DBpedia SPARQL Explorer (assuming the same prefixes as above).