SQUALL to SPARQL Translator

Your SQUALL sentence:

List all TelevisionEpisode-s whose series is res:The_Sopranos and whose seasonNumber is 1.

SELECT DISTINCT ?x1 WHERE {

?x1 a :TelevisionEpisode .
?x1 :series res:The_Sopranos .
?x1 :seasonNumber 1 .

}

Run at DBpedia SPARQL endpoint (assuming prefixes res: for resources, : and dbo: for ontology, and dbp: for properties in addition to DBpedia namespace definitions).

Load in DBpedia SPARQL Explorer (assuming the same prefixes as above).