SQUALL to SPARQL Translator

Your SQUALL sentence:

PaperX has authorList [..., what] ?

The SPARQL translation:

SELECT DISTINCT ?x1 WHERE {
?x2 rdf:rest* [ rdf:first ?x1 ; rdf:rest rdf:nil ] .
:PaperX :authorList ?x2 .
}

Run at DBpedia SPARQL endpoint (assuming prefixes res: for resources, : and dbo: for ontology, and dbp: for properties in addition to DBpedia namespace definitions).

Load in DBpedia SPARQL Explorer (assuming the same prefixes as above).


Enter a SQUALL sentence: