SQUALL to SPARQL Translator

Your SQUALL sentence:

What has a rdf:type that is-rdfs:subClassOf* the class publication?

The SPARQL translation:

SELECT DISTINCT ?x1 WHERE {
?x1 a ?x2 .
?x2 rdfs:subClassOf* :publication .
}

Run at DBpedia SPARQL endpoint (assuming prefixes res: for resources, : and dbo: for ontology, and dbp: for properties in addition to DBpedia namespace definitions).

Load in DBpedia SPARQL Explorer (assuming the same prefixes as above).


Enter a SQUALL sentence: