SQUALL to SPARQL Translator

Your SQUALL sentence:

What is the number of person-s per affiliation ?

SELECT DISTINCT ?x2 (COUNT(DISTINCT ?x3) AS ?x1) WHERE {

?x3 a :person .
?x3 :affiliation ?x2 .

} GROUP BY ?x2

Run at DBpedia SPARQL endpoint (assuming prefixes res: for resources, : and dbo: for ontology, and dbp: for properties in addition to DBpedia namespace definitions).

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