SQUALL to SPARQL Translator

Your SQUALL sentence:

Which Bridge shares a dbp:design with res:Manhattan_Bridge?

The SPARQL translation:

SELECT DISTINCT ?x1 WHERE {
?x1 a :Bridge .
?x1 dbp:design ?x2 .
FILTER (?x1 != res:Manhattan_Bridge) .
res:Manhattan_Bridge dbp:design ?x2 .
}

Run at DBpedia SPARQL endpoint (assuming prefixes res: for resources, : and dbo: for ontology, and dbp: for properties in addition to DBpedia namespace definitions).

Load in DBpedia SPARQL Explorer (assuming the same prefixes as above).


Enter a SQUALL sentence: