SQUALL to SPARQL Translator

Your SQUALL sentence:

Which Mountain has a greater dbp:elevationM than res:Nanga_Parbat?

SELECT DISTINCT ?x1 WHERE {

?x1 a :Mountain .
FILTER (?x1 != res:Nanga_Parbat) .
?x1 dbp:elevationM ?x2 .
res:Nanga_Parbat dbp:elevationM ?x3 .
FILTER (?x2 > ?x3) .

}

Run at DBpedia SPARQL endpoint (assuming prefixes res: for resources, : and dbo: for ontology, and dbp: for properties in addition to DBpedia namespace definitions).

Load in DBpedia SPARQL Explorer (assuming the same prefixes as above).