SQUALL to SPARQL Translator

Your SQUALL sentence:

Which mountain has the highest elevation ?

The SPARQL translation:

SELECT DISTINCT ?x1 ?x2 WHERE {
?x1 a :mountain .
?x1 :elevation ?x2 .
} ORDER BY DESC(?x2) LIMIT 1

Run at DBpedia SPARQL endpoint (assuming prefixes res: for resources, : and dbo: for ontology, and dbp: for properties in addition to DBpedia namespace definitions).

Load in DBpedia SPARQL Explorer (assuming the same prefixes as above).


Enter a SQUALL sentence: