SQUALL to SPARQL Translator

Your SQUALL sentence:

Which person is an author of every publication?

The SPARQL translation:

SELECT DISTINCT ?x1 WHERE {
?x1 a :person .
FILTER NOT EXISTS {
?x2 a :publication .
FILTER NOT EXISTS {
?x2 :author ?x1 .
}
}
}

Run at DBpedia SPARQL endpoint (assuming prefixes res: for resources, : and dbo: for ontology, and dbp: for properties in addition to DBpedia namespace definitions).

Load in DBpedia SPARQL Explorer (assuming the same prefixes as above).


Enter a SQUALL sentence: