SQUALL to SPARQL Translator

Your SQUALL sentence:

Which person whose rdfs:label is 'John Smith' is an author of PaperX ?

SELECT DISTINCT ?x1 WHERE {

?x1 a :person .
?x1 rdfs:label ?x2 .
FILTER (REGEX(str(?x2),'John','i') && REGEX(str(?x2),'Smith','i')) .
:PaperX :author ?x1 .

}

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