SQUALL to SPARQL Translator

Your SQUALL sentence:

Which publication-s have authorList [PersonA, PersonB, PersonC] ?

The SPARQL translation:

SELECT DISTINCT ?x1 WHERE {
?x1 a :publication .
?x1 :authorList [ rdf:first :PersonA ; rdf:rest [ rdf:first :PersonB ; rdf:rest [ rdf:first :PersonC ; rdf:rest rdf:nil ] ] ] .
}

Run at DBpedia SPARQL endpoint (assuming prefixes res: for resources, : and dbo: for ontology, and dbp: for properties in addition to DBpedia namespace definitions).

Load in DBpedia SPARQL Explorer (assuming the same prefixes as above).


Enter a SQUALL sentence: